A 7 kg bicycle moving at 11 m/s strikes a stationary 2000 kg car. The bicycle bounces backwards at 3
m/s. What is the velocity of the car after impact?

1- 0.011 m/s
2- 77 m/s
3- 21 m/s
4- 0.028

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.