A uniformly charged disk of radius 35.0 cm carries charge with a density of 7.9 x 10-3 C/m2. Determine the magnitude of the electric field on the axis of the disk at 50.0 cm from the center of the disk. Record the answer to the nearest tenth of a MN/C (mega N/C).

E= 80.71 MegaN/C

Explanation:

The radius of the disk is 35.0 cm.

The charge density is 7.9 x 10^-3 C/m^2

The distance from the center of the disk is  50.0 cm

The electric field is given by the expression as shown below:

Plugging the values in the above expression,

E = (2 *3.14 * 7.9 *10^-3 * 9 *10^9) *(1-(0.5/(sqrt(0.5^2+ 0.35^2)))

E= 80.71 MegaN/C

potential energy is directly proportional to height.

more height = more potential energy.

greatest increase in height = greatest increase in potential energy

where are the points with the greatest increase in height ?

has to be c-e or d-e .