A 4.76 kg crate is suspended from the end of a short vertical rope of negligible mass. An upward force F(t) is applied to the end of the rope, and the height of the crate above its initial position is given by y(t)=(2.80m/s)t +(0.61 m/s3 )t3 What is the magnitude of the force F when 3.71 s ?

The magnitude of the force is 64.634 newtons.

Explanation:

According to the statement, the crate is a constant mass system, whose upward force is described by the following expression:

(1)

Where:

- Force, in newtons.

- Mass, in kilograms.

- Acceleration, in meters per square second.

The function acceleration is obtained by deriving the function position twice in time:

(2)

(3)

And we expand (1) by applying (3):

Where is the time, in seconds.

If we know that and , then the magnitude of the force is:

The magnitude of the force is 64.634 newtons.

"i have always loved contemporary art and made it a general goal to work within the field. after a few nonprofit internships at museums and galleries, i decided to try the for-profit art world and was offered a job as the ad assistant at the magazine. i much prefer the pace of the for-profit art community and have stayed with the company for three years, with a promotion to an account manager last spring."

i just did this and got a 100.

a and c

c is 100% but i am confused in a