An aluminium cube of side 5cm and R. D 2.7 is suspended by a thread in alcohol of relative density 0.8o. Find the tension in thread.​

The tension in the thread is approximately 3.2103225 Newtons

Explanation:

The given parameters are;

The side length of the aluminum cube, s = 5 cm

The R.D. of aluminum = 2.7

The relative density of alcohol into which the aluminum cube is placed = 0.8

The volume of the aluminum cube, V = s³ = (5 cm)³ = 125 cm³

The mass of the aluminum cube, V = The volume of the cube

The mass of the aluminum cube, m = V × R.D. × Density of water

m₁ = 0.000125 × 2.7 × 970 = 0.327375 kg

The mass of the alcohol displaced, m₂ = 0.000125 × 0.8 × 970 = 0.097

The tension in the string, T = The apparent weight of the aluminum cube, Wₐ

∴ The tension in the thread, T = Wₐ = (m₁ - m₂) × g

Where;

g = The acceleration due to gravity ≈ 9.81 m/s²

∴ T ≈ (0.327375 - 0.000125) × 9.81 = 3.2103225

The tension in the thread, T ≈ 3.2103225 N.