A series circuit is shown in the diagram below. What is the potential drop across Rg? (Ry - 200, R2-40 Q, R3-60 , V = 60 V) (Ohrris law: V-IR)

Option C. 20 V

Explanation:

We'll begin by calculating the equivalent resistance of the circuit. This can be obtained as follow:

Resistor 1 (R₁) = 20 Ω

Resistor 2 (R₂) = 40 Ω

Resistor 3 (R₃) = 60 Ω

Equivalent Resistance (R) =?

R = R₁ + R₂ + R₃ (series arrangement)

R = 20 + 40 + 60

R = 120 Ω

Next, we shall determine the current in the circuit. This can be obtained as follow:

Voltage (V) = 60 V

Equivalent Resistance (R) = 120 Ω

Current (I) =?

V = IR

60 = I × 120

Divide both side by 120

I = 60 / 120

I = 0.5 A

Finally, we shall determine the potential drop across R₂. This can be obtained as follow:

Current (I) = 0.5 A

Resistor 2 (R₂) = 40 Ω

Voltage (V) =?

V = IR₂

V = 0.5 × 40

V = 20 V

Therefore, the potential drop across R₂ is 20 V