What is the numerical value, in meters per second squared, of the acceleration of an object experiencing true free fall?
Write your answer as a decimal.
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Idk just need points

The answer is 4f======since electrostatic force is given by    we let f be the electrostatic force when  r = 1 m    if we let  denote the electrostatic force when the distance is decreased so that r = 0.5m, then    we established earlier that f = kq₁q₂. therefore    the force will now be 4f.

According to the equation which describes the relation between the resistance, voltage and the current intensity [tex] v= i * r[\tex]where v is the voltage in volts, i is the current intensity in amperes, and r is the resistance in ohms.so for a giving v and r (substitute in the previous equation)120= 0.6 i (divide both sides by 0.6)i = 120/0.6i = 200 amperes