A 97.0 kg ice hockey player hits a 0.150 kg puck, giving the puck a velocity of 48.0 m/s. If both are initially at rest and if the ice is frictionless, how far does the player recoil in the time it takes the puck to reach the goal 14.5 m away

s₁ = 0.022 m

Explanation:

From the law of conservation of momentum:

where,

m₁ = mass of hockey player = 97 kg

m₂ = mass of puck = 0.15 kg

u₁ = u₂ = initial velocities of puck and player = 0 m/s

v₁ = velocity of player after collision = ?

v₂ = velocity of puck after hitting = 48 m/s

Therefore,

negative sign here shows the opposite direction.

Now, we calculate the time taken by puck to move 14.5 m:

Now, the distance covered by the player in this time will be:

s₁ = 0.022 m

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