A force parallel to the xx-axis acts on a particle moving along the xx-axis. This force is associated with potential energy U(x)U(x) given by U(x)=αx4U(x)=αx4 , where ααalpha = 0.770 J/m4J/m4 . Part A What is the direction of the force when the particle is at x = -0.800 mm?

i think if it were me i whould divide 300 dide 15

step-by-step explanation:

  the unit of the measure =

explanation:

  the property that is quantified by the energy needed per of material to raise the temperature by one.

  si unit of energy = joule (j)

  si unit of temperature = kelvin (k)

  si unit of mass of material = kilogram (kg)

the property that is quantified by the energy needed per of material to raise the temperature by one is called specific heat.

the unit of specific heat is

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle