The flux of the electric field (24 space N divided by C )i with hat on top space plus space (30 space N divided by C )j with hat on top space plus space (16 space N divided by C )k with hat on top spacethrough a 2.0 m2 portion of the yz plane is: A. 23 N/C B. 92 N/C C. 48 N/C D. 140 N/C

 Ф = 28  

Explanation:

The electric field in a region of space is equal to

       E = (24 i + 30 j + 16 k)  N/C

indicate that we want to calculate the flow through a surface of A = 2 m² in the yz plane, therefore this area is defined by its modulus and the normal vector

        A = 2 i

flow is the field through the plane

       Ф = E . A

we calculate

      Ф = (24 i + 30 j + 16 k). 2 i

let's remember that

       i.i = 1

       i.j = i.k = 0

      Ф = 28  

car a and b are moving in opposite directions

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