Question: A NEO distance from the Sun is 1.17 AU. What is the speed of the NEO (round your answer to 2 decimal places)

  v = 2.75 10⁴ m / s

Explanation:

For this exercise we must use Kepler's third law which is an application of Newton's second law to the solar system

            F = ma

where force is the force of gravity

            F =

acceleration is centripetal

             a =

we substitute

           G m M / r² = m v² / r

            = v²

           v =

indicate that the radius of the orbit is r = 1.17 AU, let's reduce to the SI system

            r = 1.17 AU (1.496 10¹¹ m / 1 AI) = 1.76 10¹¹ m

let's calculate

         v = Ra (6.67 10-11 1.991 10 30 / 1.76 10 11

         v = ra 7.5454 10 8

         v = 2.75 10⁴ m / s