There are two sets of resistors joined in series in a circuit. Set 1 has two resistors of 10Ω and 40Ω in parallel combination. Set 2 has three resistors of 20 Ω, 30 Ω and 60 Ω in parallel combination. A potential difference of 12 V is applied across the combination.​

There are two sets of resistors joined in series in a circuit. Set 1 has two resistors of 10Ω and 40Ω in parallel combination. Set 2 has three resistors of 20 Ω, 30 Ω and 60 Ω in parallel combination. A potential difference of 12 V is applied across the combination.

Two set of Parallel resistors

Contains two resistors of --> 10Ω and 40Ω

Contains three resistors of --> 20 Ω, 30 Ω and 60Ω

Potential Difference Of 12 V

Draw a circuit diagram to represent this arrangement Calculate

(a) the total resistance and

(b) the total current flowing in the circuit.

FOR DIAGRAM REFER ATTACHMENT!

First we calculate the total resistance of each parallel combination:-

FIRST SET Contains two resistors of 10Ω and 40Ω

so total resistance-->

SECOND SET Contains three resistors of 20 Ω, 30 Ω and 60Ω

so total resistance-->

Now by having Total Resistance of Set one and set two we can add them by series formula.

Total Resistance of the circuit = 18 Ω

Potential Difference Of the circuit = 12 V

So Total current-->

1/0.14nm = 10^10/1.4 a lot

a straight line sloped