c) An aluminum tea kettle with mass 1.10 kg containing 1.80 kg of water is placed on a stove. If no heat is lost to the surroundings, how much heat must be added to raise the temperature from 20o C to 95o C

Q = 640425 J = 640.425 KJ

Explanation:

From the law of conservation of energy:

Heat Addition = Heat Gain of Water + Heat Gain of Aluminum Kettle

where,

Q = Heat addition required = ?

= mass of water =1.8 kg

= mass of aluminum kettle = 1.1 kg

= specific heat capacity of water = = 4200 J/kg.°C

 = specific heat capacity of aluminum kettle = = 890 J/kg.°C

= = change in temperature of water and kettle = 95°C - 20°C = 75°C

Therefore,

Q = 567000 J + 73425 J

Q = 640425 J = 640.425 KJ

are you like autistic or something?

xd

a and b sometimes have a positive value