Two capacitors have the same size of plates and the same distance 4 mm between the plates The potentials of the two plates in capacitor 1 are 16 volts and 16 volts The potentials of the two plates in capacitor 2 are 320 volts and 352 volts a What is the electric field inside capacitor 1

    E = -4000 N / C

Explanation:

The potential and electric field are related

         V = - E s

          E = - V / s

we reduce the magnitudes to the SI system

          s = 4 mm (1 m / 1000 mm) = 0.004 m

we calculate

          E = - 16 /0.004

          E = -4000 N / C

cant without the picture! ?

the answer is 100. i just did this lesson and got a 100% on it. : )

-fishtank