A 7.77 kg mass is moving due west at 7.77 m/s. A second mass of 8.88 kg is moving due south at 8.88 m/s. What is the magnitude of their combined velocity, in m/s, after they collide and stick together? a) 1.11 m/s
b) 3.82 m/s
c) 5.96 m/s
d) 11.8 m/s

8.362m/s

Explanation:

Given data

Mass m1= 7.77kg

Velocity v1= 7.77m/s

Mass m2= 8.88kg

Velocity v2= 8.88m/s

Apply the law of conservation of momentum for inelastic collision we have

m1v1+m2v2= (m+m2)V

7.77*7.77+ 8.88*8.88= (7.77+8.88)V

60.3729+78.8544= 16.65V

139.2273= 16.65V

Divide both sides by 16.65

V= 139.2273/16.65

V= 8.362m/s

Hence the final velocity is 8.362m/s

1 - wave length

2 - amplitude

3 - crest

4 - trough

explanation:

duh.

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.