Please answer me my question A cylindrical container with a radius of cross section 70 cm is filled with 200 litres of water . find the pressure exerted by the water at the bottom of the container.( Take g=10 m/s^2)​

1299 N/m²

Explanation:

Applying,

P = ρgh Equation 1

Where P = pressure of water at the bottom of the container, ρ = density of water, h = height of water in the container, g = acceleration due to gravity.

but,

V = πr²h Equation 2

Where V = volume of water, r = radius of the container

make h the subject of the equation

h = V/πr² Equation 3

From the question,

Given: V = 200 liters, = 200000 cm³, r = 70 cm

Constant: π = 22/7

Substitute these values into equation 3

h = 200000/[(22/7)(70²)]

h = 12.99 cm

h = 0.1299 m

Also given

Constant: g = 10 m/s², ρ = 1000 kg/m³

Substitute these values into equation 1

P = 0.1299(10)(1000)

p = 1299 N/m²

a and b sometimes have a positive value

i just did an experiment like this in my science class. also the answer is yes, it will get separated because they are two opposites meaning if they are opposite they can not attract.

hope this .!