Deepta adhivnav having weight 450N and 350N are playing see-saw. Deepta sits at a distance of 2m from the fulcrum, how far should abhinav be seated in order to balance deepta?

Explanation:

This is a torque problem where balance is achieved when the sum of the torques equal 0. The equation for torque is

where F is the force in Newtons that is perpendicular to the lever arm, and r is the length of the lever arm in meters.

450(2) = 350r and

so

r = 2.6 m

at positions a, g kinetic energy is maximum.

at position d, potential energy is maximum.

connect the batteries in series and hope