Two masses of 3 kg and 5 kg are connected by a light string that passes over a smooth polley as shown in the Figure. QL
Determine:
i. the tension in the string,
ii. the acceleration of each mass, and
iii. the distance each mass moves in the first second of motion if they start from rest​

i.

ii.

iii.

Explanation:

Let's write Newton's 2nd law for each object. We will use the sign convention assigned for each as indicated in the figure. Let T be the tension on the string and assume that the string is inextensible so that the two tensions on the strings are equal. Also, let a be the acceleration of the two masses. And and

Forces acting on m1:

Forces acting on m2:

Combining Eqn(1) and Eqn(2) together, the tensions will cancel out, giving us

or

Solving for a,

We can solve for the tension by using this value of acceleration on either Eqn(1) or Eqn(2). Let's use Eqn(1).

Assuming that the two objects start from rest, the distance that they travel after one second is given by

the chart show the masses and velocities of two colliding objects that stick together after a collision.

according to the law of conservation of momentum, the momentum of the object after the collision is  

answer

1,500

kg • m/s.