two electrons are separated by 1.10m, What is the magnitude of the electric force each electron exerts on the other?

4.56×10¯⁷¹ N

Explanation:

From the question given above, the following data were obtained:

Distance apart (r) = 1.10 m

Force (F) =?

NOTE:

Gravitational constant (G) = 6.67×10¯¹¹ Nm² /Kg²

Mass of electron = 9.1×10¯³¹ Kg

Mass of the two elections = M₁ = M₂ = 9.1×10¯³¹ Kg

Thus, we can obtain the force of attraction between the two elections as illustrated below:

F = GM₁M₂ / r²

F = 6.67×10¯¹¹ × (9.1×10¯³¹)² / (1.1)²

F = 4.56×10¯⁷¹ N

Thus, the force of attraction between the two elections is 4.56×10¯⁷¹ N

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