If a lever lifts a load four times the effort applied and effort distance is 5 times the load distance, calculate its efficiency​

If effort distance was 4 times, efficiency would be 100%.

Since it takes 5 times for effort distance, efficiency drops to output/input

output is 1*F

input is (1/4*F)*5

so: F/1/5*F/4 = 4F/5F = .8 or 80%

atomic = no of protons.

mass number-atomic number = neutron number

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