What is the length x of the side of the triangle below

you didn't post any triangles. Thus, the question could not be answered.

The given triangle is a right triangle.

The length of the hypotenuse is 2.52.5 units.

The given angle is 39\degree39° .

The unknown side xx is adjacent to the given angle.

We can therefore use the cosine function to find xx .

Recall the mnemonics CAH.

This means that;

\cos\theta=\frac{Adjacent}{Hypotenuse}cosθ=

Hypotenuse

Adjacent

This implies that,

\cos39\degree=\frac{x}{2.5}cos39°=

2.5

x

We multiply both sides by 2.52.5 to get,

2.5\cos39\degree=x2.5cos39°=x

x=2.5(0.7771)x=2.5(0.7771)

We evaluate to get

x=1.94x=1.94

Therefore the length xx of the side of the triangle is 1.91.9 units to the nearest tenth.

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