A 5kg block is pushed 3m at a constant velocity up a vertical wall by a constant force applied at an angle of 37 degree with the horizontal, if the coefficient of kinetic friction between the block and the wall is 0.3. what is the work done by the force on the block?

The work done by the force on the block is:

The direction of motion here is in the y-direction, so we need to find the component of the force in this direction.

Using trigonometric functions:

This component is in the positive y-direction.

Now, there is a friction force between the block and the wall, so we need to find the friction force.

Where:

Let's use the first Newton's Law to get F.

F(y) is upward (+) and F(f) and the weight is downward (-).

Factoring F in the left side:

Therefore, the work done will be:

You can learn more about work definition here:

answer: he got 23

explanation:

a

explanation:

no diagram was provided, but i'm guessing it's the one i've attached to my answer.

here, a mechanical force turns the rod.   this generates an electric current in the coil, which powers the bulb.