Two students try to move a heavy box. One pushes with the force of the 80N while the other pulls with a force of 40N in the same direction. What is the work done by each boy after the box is moved 10 meters? Show your equation.

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Explanation:

Force applied by first student (F1) = 80 N

Force applied by the second student (F2) = 40 N

Displacement (d) = 10 m

Work done by first student (W1) = F1d = 80*10 = 800 J

Work done by second student (W2) = F2d = 40*10 = 400 J

Hence, the work done by the pushing student is 800 J and that by pulling student is

it about 600 mph from what i calculated

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer