A communications satellite is in a synchronous orbit that is 3.6 x 107 m directly above the equator. The satellite is located between two cities almost on the equator that are separated by a distance of 2.9 x 106 m. Find the time it takes for a telephone call to go by way of satellite between these cities. Ignore the curvature of the earth.

Sorry i don’t know what to do

You need to be more specific.  i really don't know what a "motion map" is.you can draw a graph of an object's position, distance, displacement, speed,velocity, or acceleration versus time, or you can draw a graph of the object's x-position versus its y-position and not give any information about time at all.if the graph presents position or displacement against time,  then constant velocity is a straight line . . i.e. a line that has  constant slope.if the graph shows speed against time, then constant velocityis a horizontal piece of line.if the graph shows acceleration against time, then constant  velocity is a piece of line that lies on the x-axis . . it's value is zero.