Una masa de 10,0 kg se mueve hacia arriba en un plano inclinado con una fuerza de 99,9 N. Si el coeficiente de fricción cinético es de 0,400, ¿Cuál es el trabajo realizado por la fuerza de fricción cinética si la masa se desplaza 15,0 metros hacia arriba?
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19 hertz bruh u trippin? ?

Answer: 1.4 seconds which is the third optionexplanation: current is defined as the flow of charge per timetherefore, the equation that relates current, charge and time can be expressed as follows: i = δq / δtwhere: i is the current given = 1.8 ampereδq is the charge given = 2.5 coulombδt is the time required for the flow of the given charges to give the 1.8 ampere.substitute with the givens in the above equation to get the time as follows: 1.8 = 2.5 / δtδt = 2.5 / 1.8 = 1.38888 which is approximately 1.4 secondshope this was !