a body starts moving from rest and attains the acceleration of 2 metre square calculate the velocity at the end of 310 minutes and also find the distance traveled by it during that time

Here, we have

Initial velocity, u = 0 m/s (As starts from rest)

Acceleration, a = 2 m/s².

Time taken, t= 310 min = 310 × 60 = 18600 seconds

To Find,

Final velocity, v and,

Distance covered, s

Formula to be used,

1st and 3rd equation of motion,

v = u + at and v² - u² = 2as

So, putting all the values, we get

V = u + at

v = 0 + 2 x 18600

v = 2 x 18600 → v = 37200 m/s.

Hence, the final velocity is 37200 m/s.

Now, Distance covered,

v² - u²= 2as

(37200 )² - (0)² = 2 x 2 x s

1,383,840,000 = 4s → s = 345,960,000m

Hence, the distance covered is 345,960,000 m.

the minimum amperage that the current in this wire would have to have so that its weight is completely supported by the magnetic force due to earth's field, assuming that no other forces except gravity act on it