Forces is F1(east) and F2 are simultaneously applied to a 30kg mass. When f2is east , a = 5.0 m/s2 east and
When F2 is west a=10m/s² east - Determine the
Magnitude of f1 and f2

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j

b. false

explanation:

suppose a rock in free fall is dropped off a cliff. after falling for 5 seconds, its speed would not be 100 m/s.