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A ball is thrown upward at 15 m/s (v= +15 m/s). Neglecting air friction, it will return to the point from which it
was thrown with a downward speed of 15 m/s (v=-15 m/s). If the acceleration due to gravity is -10 m/s2, how
long will the ball remain in the air?
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Answer59.2kg; /

Since you have not included the experiment situation and the data, of course, i can not give you specific details about it. but i can you with this question.1) i will assume that the motion is projectile (parabolic) motion.2) yes, the horizontal distance depends on the horizontal velocity as, naming vx the horizontal velocity and t the time, it is: x = vx × t3) now, observe that the flight time depends on the vertical velocity as, naming voy the initial vertical velocity, t the time and y the vertical distance before reaching the ground: y = yo + voy×t - gt² / 2.the higher the initial vertical velocity (voy) the longer the object will be flying and so t will be higher in the equation for the horizontal distance.that explains the relationship between the horizontal distance and the horizontal velocity.

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