Physics, 09.09.2021 04:40 skarimi740

Can someone help me with this one? means a lot.

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Answer from: Quest

the velocity you are looking for is made up of two parts: horizontally velocity, vh, and its vertical velocity, vv. the actual velocity of the ball will be these two parts added together, and because velocity is a vector then they will need to be added vectorially.

neglecting air resistance etc etc.,

the horizontal velocity component will be constant (because there is no accelerating force in the horizontal direction.

vh = 8 ms-1

the vertical velocity component has an accelerating force: 'g'.

using v = u +at where a = g = 9.81 ms-2.

the vertical component of velocity, vv = 0 + gt = vv =9.81 x 2

vv = 19.62 ms-1 . the zero appears because the virtical component of velocity at time t=0 is zero. remember, the ball was thrown horizontally.

how fast it will be moving (it actual path (being a parabola )) will be the vector sum of these two.

adding vectorally gives: -

v = sqr root (8^2 + 19.62^2) = sqr root(64+384.9) = 21.18 or 21.2 ms-1

Answer from: Quest

he kicked it 10 feet straight up into the air? i think this works.

Answer from: Quest

im sorry i dont know

Answer from: Quest

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.

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