A ball is thrown straight up from ground level. It passes a 2-m-high window. The bottom of the window is 7. 5 m off the ground. The time that elapses from when the ball passes the bottom of the window on the way up, to when it passes the top of the window on the way back down is 1. 3 s. Required:
What was the ball’s initial velocity?

i. like it i'm gonna edit it tomorrow

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i just did this and got a 100.

the bal will not change its velocity.

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west