A wheel turns with angular speed of 30 rev/s is brought to rest with constant acceleration. It turns 60 rev before it stops. Calculate its angular in rad/s²​

Since the angular acceleration α is constant,

0² - (30 rev/s)² = 2α (60 rev)

Solve for α :

α = -(30 rev/s)²/(120 rev) = -7.5 rev/s²

One revolution corresponds to an angular displacement of 2π radians, so

α = (-7.5 rev/s²) × (2π rad/rev) ≈ -47.12 rad/s²

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation: