A cyclist maintains a constant velocity of 5 m/s headed away from point A. At some
initial time, the cyclist is 248 m from point A.
What will be his displacement from his
starting position after 49 s?
Answer in units of m.

Hi there!

We can use the equation:

d = x₀ + vt, where:

x₀ = initial distance from the reference point

v = velocity (m/s)

t = time (sec)

Plug in the given values:

d = 248 + 5(49)

d = 493m

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