given an oil droplet of mass 0.9mg and density 918kg/m^3 that spreads out into a circle of a radius 41.8cm on the water surface what is the diameter of the oil molecule​

The diameter of the oil molecule is  .

Explanation:

Mass of the oil drop =

Density of the oil drop =

Volume of the oil drop: v

Thickness of the oil drop is 1 molecule thick.So, let the thickness of the drop or diameter of the molecule be x.

Radius of the oil drop on the water surface,r = 41.8 cm = 0.418 m

1 cm = 0.01 m

Surface of the sphere is given as: a =

Volume of the oil drop = v = Area × thickness

The thickness of the oil drop is  and so is the diameter of the molecule.

i think it’s a. this is because if they measured the mass of something with a mass of 150g, then their final answer would have to be approximately 150g. though all of their answers are almost 150, rosa and tran have the closest answers (or the exact answer) to the accurate one.