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Present
A
TA
B
2
U
to shiper
o and
Equation of Motion
.
Solution: Substituting 1.5 m for the initial position
and 3.0 m/s for the constant velocity in the
equation of motion gives the following:

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energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j