A cannon is fired at 30° above the horizontal line with a velocity of 210 m/s from the edge of a cliff 125 m high. Calculate where the cannonball lands on the level plain below.

Question:

A cannon is fired at  

30

∘

above the horizontal with a velocity of  

200

m

s

from the edge of a  

125

m

high cliff. Calculate where the cannonball lands on the level plain below.

Projectile Motion:

An object or particle that is thrown near the Earth's surface experiences a projectile motion and creates a parabolic path. Its velocity at each point or time t is expressed as the sum of horizontal and vertical components. The horizontal velocity is constant while the velocity along the y-axis is affected by the gravity.

Answer and Explanation:

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We know that the velocity along the x-axis is constant and the total horizontal distance traveled is  

x

=

v

o

cos

θ

t

. Here, the time t i...

See full answer below.

a=d/t

a="triangle"v/t

explanation:

a = acceleration

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards