The ratio for the cross section areas of the
tube is A2
A1
= 0.535, the di...
![subject](/tpl/images/cats/fizika.png)
The ratio for the cross section areas of the
tube is A2
A1
= 0.535, the difference in the
pressures is P1 − P2 = dP = 29.9 Pa , and the
density of the fluid is 2.97 kg/m3
.
Find the speed of the fluid near the right
hand end of the tube (i. e., find v2).
Answer in units of m/s.
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Answers: 1
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