Physics, 10.10.2021 22:00 poohmoney

A 100g object falls 5 meters. How fast do you determine it is moving when it hits the ground?

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Approximately $9.9\; \rm m\cdot s^{-1}$ , assuming that this object started from rest, $g = 9.81\; \rm m \cdot s^{-2}$ , and that air resistance on this object is negligible.

Explanation:

If the effect of drag on this object is negligible, the acceleration of this object would be constantly equal to , the gravitational field strength ( $g \approx 9.81\; \rm m\cdot s^{-2}$ near the surface of the earth.)

Since acceleration is constant, it would be possible to find the final velocity of this object using SUVAT equations.

Let

and

denote the final and initial velocity of this object, respectively. Under the assumption that this object started from rest, $u = 0\; \rm m \cdot s^{-1}$ .Let

denote the acceleration of this object. Under the assumptions above, $a = g = 9.81\; \rm m\cdot s^{-2}$ .Let

denote the displacement of this object. In this question, $x = 5\; \rm m$ .

The following SUVAT equation would apply:

$v^{2} - u^{2} = 2\, a\, x$ .

Rearrange to find an expression for :

$\begin{aligned}v^{2} &= 2\, a\, x + u^{2}\end{aligned}$ .

$\begin{aligned}v &= \sqrt{2\, a\, x + u^{2}}\end{aligned}$ .

Substitute in the values $u = 0\; \rm m\cdot s^{-1}$ , $a = 9.81\; \rm m\cdot s^{-2}$ , and $x = 5\; \rm m$ . Evaluate the expression to find the value of :

$\begin{aligned}v &= \sqrt{2\, a\, x + u^{2}} \\ &= \sqrt{2 \times 9.81\; \rm m\cdot s^{-2} \times 5\; \rm m} \\ &\approx 9.9\; \rm m\cdot s^{-1}\end{aligned}$ .

Therefore, under these assumptions, the velocity of this object would be approximately $9.9\; \rm m\cdot s^{-1}$ right before it hits the ground.

Answer from: Quest

Divide 108.2 x 10^6 into 1.5 x 10 and the result will be in au (astronomical units)

Answer from: Quest

Is a vector quantity that refers to "the rate at which an object changes its position." imagine a person moving rapidly - one step forward and one step back - always returning to the original starting position. while this might result in a frenzy of activity, it would result in a zero velocity. because the person always returns to the original position, the motion would never result in a change in position. since velocity is defined as the rate at which the position changes, this motion results in zero velocity. if a person in motion wishes to maximize their velocity, then that person must make every effort to maximize the amount that they are displaced from their original position. every step must go into moving that person further from where he or she started. for certain, the person should never change directions and begin to return to the starting position.

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