What is the best estimate for the time required for an object in free fall (Vi = 0) with air resistance to travel 313.6 m. a little more than 8 seconds

a little more than 7 seconds

a little less than 8 seconds

a little less than 10 seconds

Third option

Explanation:

We will find the answer by using the formulas to calculate distance during a free fall...

t = fall time

g = free all acceleration

We know that the initial velocity is 0, and the acceleration the object has before it hits the ground is 313.6 m, we also know that acceleration while free falling is a constant 9.80665 meters per second (default meters per second) and that is with air resistance (which is also constant) so we are going to use 8 seconds because it is mentioned twice in the options provided. Knowing all of this data we can correctly substitute to find the amount of time using the formulas of free fall.

s = (1/2)gt^2 = 0.5 × 9.80665 × 8^2 = 313.8m

But since we want the object to travel 313.6m the time it needs has to be a little less then 8 seconds which is the third option.

Hope this helps.

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees. 

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.