Particle A passes a point with an initial velocity of 12.8 m/s and an acceleration of 4.22 m/s^2. Particle B has a 41 m head start at 5.79 m/s with an acceleration of 3.36 m/s^2. At what time will A pass B? Answer in units of s.

Answer: 1.4 seconds which is the third optionexplanation: current is defined as the flow of charge per timetherefore, the equation that relates current, charge and time can be expressed as follows: i = δq / δtwhere: i is the current given = 1.8 ampereδq is the charge given = 2.5 coulombδt is the time required for the flow of the given charges to give the 1.8 ampere.substitute with the givens in the above equation to get the time as follows: 1.8 = 2.5 / δtδt = 2.5 / 1.8 = 1.38888 which is approximately 1.4 secondshope this was !

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