A toy train has a mass of 2.00 kg. The engine of the toy train pulls the train with a force of 10.4 N toward the left.
The friction between the wheels of the train and the rails
oppose this motion. The train accelerates at 1.10 meters
per second squared in the same direction under these
forces.
What is the magnitude of the friction force acting on this
train?
Select one:
12 N
2.2 N
o
O
8.2 N
8.6 N
О.

Iwould say a is accurate

Answer: 1.4 seconds which is the third optionexplanation: current is defined as the flow of charge per timetherefore, the equation that relates current, charge and time can be expressed as follows: i = δq / δtwhere: i is the current given = 1.8 ampereδq is the charge given = 2.5 coulombδt is the time required for the flow of the given charges to give the 1.8 ampere.substitute with the givens in the above equation to get the time as follows: 1.8 = 2.5 / δtδt = 2.5 / 1.8 = 1.38888 which is approximately 1.4 secondshope this was !

Mass / weighthope it !