Engineers are developing new types of guns that might someday be used to launch satellites as if they were bullets. One such gun can give a small object a forward velocity of 3.5 km/s while moving it through a distance of only 2.0 cm. What acceleration does the gun give this object?

Using

Vf 2 = Vi2 +2a*S, S = distance moved

Given Vf = 3.4 *103 m/s Vi = 0 , S = 1.8 * 10 -2 m

a = 3.4 *3.4 * 106 / (2*1.8 *10 -2 ) m/s2 , Get a from here

Also Vf = Vi +a*t

3.4*103 = a* t

Plug in a and get t ( time interval of acceleration )

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the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm