Physics, 09.11.2021 22:40 mia7791

Một vật được ném xiên với vận tốc ban đầu 2√2 (m/s) hợp với phương ngang góc 45o.
a) Sau bao lâu (kể từ lúc ban đầu) thì vật đạt độ cao cực đại?
b) Tính độ cao cực đại của vật (so với vị trí ban đầu của vật).

Answers: 3

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Một vật được ném xiên với vận tốc ban đầu 2√2 (m/s) hợp với phương ngang góc 45o.
a) Sau bao...

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Một vật được ném xiên với vận tốc ban đầu 2√2 (m/s) hợp với phương ngang góc 45o. a) Sau bao lâu (kể từ lúc ban đầu) thì vật đạt độ cao cực đại? b) Tính độ cao cực đại của vật (so với vị trí ban đầu của vật).

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Một vật được ném xiên với vận tốc ban đầu 2√2 (m/s) hợp với phương ngang góc 45o.
a) Sau bao lâu (kể từ lúc ban đầu) thì vật đạt độ cao cực đại?
b) Tính độ cao cực đại của vật (so với vị trí ban đầu của vật).