2. You throw a 2 kg ball upward with an initial velocity of 20 m/sec. About 4 seconds later, the ball returns and you catch it.
9.8 m/s
0.0 m/s
o o o o
4.9 m/s
19.6 m/s
CLEAR ALL
What is the magnitude of the velocity at the top of the ball's upward path? (Neglect
Friction and assume on or near the earth's surface.]

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.

Mass and velocity are the 2 factors used to calculate kinetic energy. the equation for kinetic energy is (1/2)mv^2. hope this !

Perpendicular to the wave motion