If the distance travelled by a body in time t is given by x = at + bt^2, then what will be the acceleration of the body?

Explanation:

the general form of the position equation with constant acceleration is

s = s₀ + v₀t + ½at²

where

s = position at time = t

s₀ = original position with respect to the selected origin

v₀ = velocity at t = 0

a = constant acceleration

comparing to the equation

x =      + at + bt²

shows that

s₀ = 0

v₀ = a

½a  = b

a = 2b

acceleration will be twice the b value

for this one it would be d bump/forearm pass

higher potential

explanation:

because it is in a high speed so it must move into a of high potential