Question 2 You can make the puck travel in complex
ways by placing a set of charges around on
the field. So, here’s your game challenge:
Arrange sources charge around to propel
the puck from its starting position into the
goal. That’s pretty easy for a straight shot;
you just put a negative charge behind the
goal. But what if there are barriers along
the way? This is a real test of your physical
understanding, including Newton’s laws of
motion and electrostatic forces. Game’s on!

Part A

On the control bar, check the Trace and
Field boxes. The game has three Difficulty
levels. Start with Difficulty level one and
arrange source charges to get the puck
into the goal. Once you’ve made a score at
any level, increase the Difficulty level. Take
a screen capture of two of your most
difficult goals and paste them here. At least
one of these should be at Difficulty level 2
or 3.

When you go to ask a qustion there will be a picture of a paper clip looking thing and then it will pop up your files and you click on the imajes and then you up load it

    m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| =  √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| =  √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| =  14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s