Find the horizontal velocity component and vertical velocity component, given distance travelled = 1.6 meters, time of flight = 0.12seconds and launch height = 0.05meters

grav force prop 1/r squared 2r all squared is 4rsquared 1/4rsquared quartered

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.