) A centrifuge having a length of the bowl of 0.1016 is rotating at = 1000 ൗ at an angle of = 15° with respect to vertical axis. a) Calculate the centrifuge force developed in terms of gravity force? b) Compare this force to that for a bowl with a radius of 0.2032 rotating at the same

diagram is missing, but i will try to explain your doubt.

answer:

amplitude is the maximum displacement or distance moved on a point of a vibrating body or wave measured from its equilibrium position.it is equal to half the length of vibration path.

dang that balls went far

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm