A pilot wishes to fly from airport A to airport B. Airport B is located due south from airport A. The pilots aircraft averages a speed of 160 mi/hr. If the pilot is flying in a wind which blows out of the west at a speed of 40 mi/hr, then the pilot should head his plane in the direction of vector ...

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W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

It really doesn't matter for any of the questions that you've listed.

Answerit increases at a steady rate;