A 0.60 kg rubber ball has a speed of 1.5 m/s at point A and kinetic energy 7.6 J at point B Find a) the ball's kinetic energy at A. Answer in units of J.

b) the ball’s speed at B. Answer in units of m/s.

c)the total work done on the ball as it moves from A to B. Answer in units of J.

it is the second option.

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west

r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.