the motion of a particle along a straight line is represented by the position versus time graph above. at which of the labeled points on the graph is the magnitude of the acceleration of the particle greatest?

that would be because of both gravity and friction. so     c

im srry but ur wrong the answer is d a smooth rock, some red dirt, and an empty bird's nest.

total distance/total time

(85 + 82)/(5+3)

167/8

20 just over

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft