Calculate the first and second velocities of the car with two washers attached to the pulley, using the formulas v1 = 0. 25 m / t1, and v2 = 0. 25 m / (t2 â€" t1) where t1 and t2 are the average times the car took to reach the 0. 25 and the 0. 50 meter marks. Record these velocities, to two decimal places, in Table E. What is the first velocity of the car with two washers at the 0. 25 meter mark? m/s What is the second velocity of the car with two washers at the 0. 50 meter mark? m/s.

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Distance covered, s = 8ft - 4ft = 4 ftinitial velocity, u = 34 ft/sthe acrobat is moving upwards and therefore, a = -g = -9.81 m/s^2 = 32.19 ft/s^2applying equation of motion; s = ut -1/2gt^2then,4 = 34t -1/2*32.19t^24 = 34t - 16.095t^2rearranging; -16.095t^2 + 34t - 4 = 0solving the quadratic equation; t = {-34 +/- sqrt [34^2 - 4(-16.)]}/2(-16.095) = 1.06 +/- 0.93 = 0.13 or 1.99the acrobat will take 0.13 seconds to be at 8 ft above the ground. additionally, once at the maximum height, the acrobat will move down and be at the same spot (that is height) after 1.99 seconds moving down.